what are the odds of flopping a flush if you have suited cards?
what are the odds of flopping a flush if you have suited cards?
This is a simple question.
If you're into playing here for a while I'll tell you, but if not, then you should stick with 'playing the player.'
Add the percentages together.
14 /52 = 26%
2/50 = 4%
12/50 = 24%
9/47 = 19%
17% of the time if you're the only person playing.
las probabilidades son de 118 a 1 in texas holden...
^^^ what he said
What?? lol
The math is simple, to get the answers that were given, you just have to figure odds of getting that suited card you need for all three cards on flop. To get the first one odds are : the 11 suited cards left over 50 total cards left or 11/50, for the 2nd flopped card odds are 10 needed suited cards left over 49 or 10/49 and for the third, same pattern, 9/48. So odds of all 3 happening is 11/50 X 10/49 X 9/48 = 990/117600 which comes to 1/118.78, which is how they come up with 1 in 118 actually closer to 1 in 119.
i dont know this one
And chances getting dealth pocket Aces is 1 in 221 but it seems way more than that!
0.84 %
I'm just being an idiot. Does multiplying the ratios take out the zero clause?
For instance, 1/118 = 0.008 ROUNDED to 0.01 right?
Well, if you add the 14/52 clause like I did above the result is 18%, right? What a coincidence!
P.S. I was just trying to screw with the op. :)
P.S.S. Wasn't it the Greeks and not the creators of the 10 digit system that decided to multiply the result of ratios by 100? It's all the same to me.