if there are 4 diamonds on the board? And there is only 1 other person in the hand, what are odds that other person has atleast 1 diamond in his hand?
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if there are 4 diamonds on the board? And there is only 1 other person in the hand, what are odds that other person has atleast 1 diamond in his hand?
due the math ..total number of cards plus total number of players on table plus total amount of diamonds in the deck..try it out..lol
fold fold fold fold fold fold fold fold ccheck raise all in
not enough information how was the hand played out and based on the player your playing against more information is needed
You know 7 cards. Your 2 and the 5 on the board. (The number of other players does not change this.) There are 45 other cards and 9 are Diamonds. 1 in 5 is 20%. He has 2 cards so 2 in 5 is 40%
Of course the action of the hand should give you some idea of what he might have. Did he play like he was on a draw? Was he agressive until the 4th Diamond hit. Is he a bluffer or trapper? That should tell you more than worrying about pot odds.
It's 50/50. Either he does or he doesn't. Ha Ha Ha... Sorry, little punchy, just got runner runnerred to lose a tournament AJo > QQ with a Q on the flop. It all went in post flop too... +1 to mawoyto
13 Diamonds in a deck, minus 4 on the table, equals 9 outs.
9 outs out of 52 cards in a deck, Minus the 7 cards that are already seen by you ( 5 on table, 2 Hole )
9/45 = 20%
So basically, about 1/5
All this is assuming you do not hold one in your hands as well.
Edit : As posted while I was posting is right ! I forgot to double up considering he has 2 cards.
40% is right.
You've definitely gotten the math answer to your question but it comes down to this, how did your opponent play the hand. More information is needed.
it is not only this hand but other hands as well factor into this decision. there was a lot of info left out of the question for a solid answer but they supply you with the math you needed.